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sinx*tanx-1=tanx – sinx
find the general solution.

Leo Pixie , 11 Years ago
Grade 9
anser 1 Answers
Arun Kumar
Hello Student,
\\sinxtanx-1=tanx-sinx \\=>tanx(sinx-1)+sinx-1=0 \\=>(sinx-1)(tanx-1)=0 \\=>tanx=0 $ or $sinx =1 \\=>x=n\pi$ or $x=n\pi+(-1)^{n}{\pi \over 2}

Thanks & Regards
Arun Kumar
Btech, IIT Delhi
Askiitians Faculty
Last Activity: 11 Years ago
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